# Line slope calculator 5x+2y=10

**Straight line given by points A[0; 5] and B[2; 0]**

## Calculation:

**Slope-intercept form of line:**y = -2.5x+5

**Canonical form of the line equation:**5x+2y-10 = 0

**Parametric form of the line equation:**

x = 2t

y = -5t+5 ; t ∈ R

**Slope:**m = -2.5

**Slope angle of line: φ =**-68°11'55″ = -1.1903 rad

**X intercept:**x

_{0}= 2

**Y intercept:**y

_{0}= q = 5

**Distance line from the origin:**d

_{0}= 1.857

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(2; -5)

**Normal vector: n =**(5; 2)

**Midpoint of the segment AB: M =**[1; 2.5]

**Perpendicular Bisector equation:**2x-5y+10.5 = 0

**Vector OA = (0; 5) ; |OA| = 5**

**Vector OB = (2; 0) ; |OB| = 2**

**Scalar product OA .OB = 0**

**Angle ∠ AOB = 90° = 1.5708 rad**